LL_1.DELETE_ELEMENT_BY_VALUE(‘PATIENT 6’)
IN [21]:

LL_1.TRAVERSE_LIST() ## IT WORKS! NOW WE HAVE ONE PATIENT 6 AS ORIGINALLY INTENDED, WHAT DOES THIS TELL YOU ABOUT THE SCRIPT?
PATIENT 6
PATIENT 0
PATIENT 5
PATIENT 4
PATIENT 3
PATIENT 2
PATIENT 1
1) DEVELOP A CLEAR() FUNCTION TO THE ABOVE DEFINED LINKEDLIST CLASS WHICH CLEARS/DELETES ALL ELEMENT FROM THE LIST.
2) DEMONSTRATE THAT IT WORKS.

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